Math solution-1

Hello, guys here is the set of solutions ,to yesterday's questions  ..

1) Let the cost of each pen, each eraser and each refil be Rs p, Rs e and Rs r resp then
 
   5p+7e+9r=46-(1)
   2p+5e+8r=36-(2)
   - -
   __________________
   3  2     (take diff of any two of the 3 variabels using trial and error  )

Now multiply (1) by 3 and (2) by 2 and then subtract smaller value 4m larger value
we get
   11(p+e+r)=66 =>p+e+r=6

2)
   concept of men-days is used.
   work done= men* number of days ->(1)

   Therefore from (1)
   
   work done = 10 *8 ->(2)

3)The given word is "LASER" .Alphabetical order of the letters of the given word is:
   A,E,L,R,S.

    Number of words beggining with A=4!=24
    Number of words beggining with E=4!=24
    Number of words beggining with LAE=2!=2
    Number of words beggining with  LAR=2!=2
    Number of words beggining with LASER=1
    Required word is LASER

4) First thing to remember in speed and distance is don't be frigtened by seeing the size of the problem.
    
  At the end of the day only formula in T&d is (distance= speed * time)

 Let the speed of the motorcyclist be ukmph and lenght of the train be L km.

 L 
    __________ =    4    ->(1)  (Time taken  is given by Lenght / Speed)
      45+u      (Bike and train in opposite directions  so sum of speeds)

 L
    __________  =   6              ->(2) (Time taken  is given by Lenght / Speed)
       45-5          (Cycle  and train in same  diection so difference of speeds)


solving we get u = 15.
   
  Therefore,      Rank of the word 'LASAR' =24+24+2+2+1=53 

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